[SOLVED] How to define a constant based on Lazarus Build Mode ?

[440bx]

Hello,

Consider a program that has two (2) build modes defined in Lazarus "Win64 Debug" and "Win64 Release".

Is it possible to define the value of a compiler constant based on that build mode, e.g,

Code: Pascal  [Select][+][-]

1. {$if BuildMode = "Win64 Debug"}   // something functionally like this but that works!
2. const
3.   MODE = 'Debug';
4. {$endif}
5.  

Thank you for your help.

[440bx]

After a little more digging, I can answer my own question (which hopefully will be useful to someone in the future.):

Simply declare a compiler define depending on the build mode.  That define can then be tested in the code.

Refer to the attachment for an example.

[ASBzone]

You can even do it more effectively on the "Additions and Overrides" page.


See attached.

[440bx]

Good to know that other option too.

Thank you ASBzone. 

[Thaddy]

A better way is

Code: Pascal  [Select][+][-]

1. {$ifopt D+}// + is debug mode - is release mode

That is better because it does not rely on the Lazarus IDE.
This works in other editors too, since it is compiler configuration based.

If you did not know that, it was not solved, but now it is.....

(I can complicate things on request, but that is not the general issue)

It is all about how your fpc.cfg options are defined.
Has nothing to do with Lazarus.

[440bx]

I need to know the Lazarus build mode.  Simply knowing the debug mode is insufficient.

[Thaddy]

I need to know the Lazarus build mode.  Simply knowing the debug mode is insufficient.

Then you can use {$if defined()} // which is the same in this particular case
Lazarus itself does not do anything that is not defined in the config file, except for its own IDE options.
I thought you knew that....

The build mode is simply passed to the compiler. That is not rocket science.

[440bx]

The build mode is simply passed to the compiler. That is not rocket science.

The compiler doesn't know what the Lazarus build mode is which is what's needed in this particular case.

[Thaddy]

Of course it knows.
There are no secret options that Lazarus can send to the compiler.
THINK
This deserves my record number of devils...
 
 

Are you being stupid on purpose?

[440bx]

LOL... it's amazing how ridiculous you can get.

[n7800]

By the way, "build modes" can be defined at the level of the compiler configuration file. This works for all projects and without the IDE at all. When compiling from the command line, you can specify:

Code: Bash  [Select][+][-]

1. fpc -dMyBuildMode main.pp
2.  

and the desired "build mode" will be used.

[440bx]

By the way, "build modes" can be defined at the level of the compiler configuration file. This works for all projects and without the IDE at all. When compiling from the command line, you can specify:

Code: Bash  [Select][+][-]

1. fpc -dMyBuildMode main.pp
2.  

and the desired "build mode" will be used.

Having a Lazarus-independent method can come in very handy.  Thank you for pointing that out @n7800.