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[ SOLVED ] Json parse problem
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Topic: [ SOLVED ] Json parse problem (Read 296 times)
superc
Full Member
Posts: 235
[ SOLVED ] Json parse problem
«
on:
March 23, 2023, 08:58:26 am »
Hello,
I've a json like this:
Code: Pascal
[Select]
[+]
[-]
{
"Input": [
{
"lang": {
"bg": null,
"cs": null,
"da": null,
"de": "asdasdasdasd",
"el": null,
"en": "asdasdasdasda",
"es": "anmtrodsfsad",
"et": null,
"fr": "asdasdas",
"hr": null,
"hu": null,
"it": "asda grill",
"lt": null,
"lv": null,
"nl": null,
"pl": "asdasdasd grilla",
"pt": "asdasdasda",
"ro": null,
"ru": "\u0441\u0435\u043d\u0441\u043e\u0440\u043d\u044b\u0439 \u0433\u0440\u0438\u043b\u044c",
"sk": null,
"sl": null,
"sr": null,
"sv": null,
"tr": null
}
,
"val_par"
:
1
}
]
}
I wrote a code like this :
Code: Pascal
[Select]
[+]
[-]
var
jInput
,
jVersions
:
TJSONArray
;
js
,
o
,
t
:
TJSONData
;
str
:
string
;
i
,
c
:
Integer
;
JsonFile
:
TFileStream
;
fileStream
:
TFileStream
;
tl
:
TStringList
;
stTemp
:
string
;
begin
try
tl
:
=
TStringList
.
Create
;
tl
.
LoadFromFile
(
fileJson
)
;
js
:
=
GetJSON
(
tl
.
Text
)
;
o
:
=
js
.
FindPath
(
'Input'
)
;
if
(
o <>
nil
)
and
(
o
.
JSONType
=
jtArray
)
then
begin
jInput
:
=
TJSONArray
(
o
)
;
for
i
:
=
0
to
jInput
.
Count
-
1
do
begin
o
:
=
jInput
[
i
]
.
FindPath
(
'lang'
)
;
if
(
o <>
nil
)
and
(
o
.
JSONType
=
jtObject
)
then
begin
end
;
end
;
end
;
finally
js
.
Free
;
tl
.
Free
;
end
;
end
;
I don't understand how to reach language tags like "bg", "cs", etc...
Thanks in advance.
«
Last Edit: March 23, 2023, 11:58:50 am by superc
»
Logged
superc
Full Member
Posts: 235
Re: Json parse problem
«
Reply #1 on:
March 23, 2023, 09:05:07 am »
found it :
Code: Pascal
[Select]
[+]
[-]
o
:
=
jInput
[
i
]
.
FindPath
(
'lang'
)
;
if
(
o <>
nil
)
and
(
o
.
JSONType
=
jtObject
)
then
begin
stTemp
:
=
o
.
FindPath
(
'de'
)
.
Value
;
end
;
Logged
loaded
Hero Member
Posts: 757
Re: Json parse problem
«
Reply #2 on:
March 23, 2023, 09:12:05 am »
Code: Pascal
[Select]
[+]
[-]
uses
fpjson
;
procedure
TForm1
.
Button1Click
(
Sender
:
TObject
)
;
var
jmain
:
TJSONData
;
begin
jmain
:
=
GetJSON
(
'{"Input":[{"lang":{"bg":null,"cs":null,"da":null,"de":"asdasdasdasd","el":null,"en":"asdasdasdasda","es":"anmtrodsfsad","et":null,"fr":"asdasdas","hr":null,"hu":null,"it":"asda grill","lt":null,"lv":null,"nl":null,"pl":"asdasdasd grilla","pt":"asdasdasda","ro":null,"ru":"сенсорный гриль","sk":null,"sl":null,"sr":null,"sv":null,"tr":null},"val_par":1}]}'
)
;
showmessage
(
jmain
.
FindPath
(
'Input'
)
.
items
[
0
]
.
FindPath
(
'lang'
)
.
FindPath
(
'de'
)
.
AsString
)
;
end
;
Logged
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Get up and do something useful! Because God is the helper of those who start again
;
superc
Full Member
Posts: 235
Re: Json parse problem
«
Reply #3 on:
March 23, 2023, 11:58:37 am »
thanks, your code will help me for another function.
Logged
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) »
[ SOLVED ] Json parse problem
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